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This is the 59th Video of our Playlist "Graphs : Popular Interview Problems" by codestorywithMIK
In this video we will try to solve a good Graph practice problem of Dijkstra and BFS : Minimum Obstacle Removal to Reach Corner I | Using Already Studied Concept | Leetcode 2290 | codestorywithMIK
I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY.
We will do live coding after explanation and see if we are able to pass all the test cases.
Also, please note that my Github solution link below contains both C++ as well as JAVA code.
Problem Name : Minimum Obstacle Removal to Reach Corner I | Using Already Studied Concept | Leetcode 2290 | codestorywithMIK
Company Tags : will update later
My solutions on Github(C++ & JAVA) - [ Ссылка ]
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Summary :
The solution finds the minimum number of obstacles to remove to reach the bottom-right corner of a grid from the top-left using a modified Dijkstra's algorithm. It utilizes a priority queue to explore cells with the least obstacle count first, ensuring an optimal path is found. Each neighboring cell is evaluated, and the obstacle count is updated if a shorter path is discovered. The result is stored in a 2D array, and the minimum obstacle count to reach the destination is returned. The overall time complexity is O((m * n) log (m * n)).
✨ Timelines✨
00:00 - Introduction
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