This video gives visual demonstrations of how capacitors and low pass filters work. It shows the circuit, the equations, the time-varying inputs and outputs, and the frequency response plot.

Start with visual of capacitor and current and voltage and time

Show applied DC voltage and voltage across capacitor

Note current initially flows until capacitor 'charges up' to source voltage level

Capacitor discharge in same time

Note that increasing capacitance makes it take longer to charge

Increased capacitance corresponds to decreased impedance per the equation

Which means it's not 'impeding' as much on stopping the current from flowing through it.

Discuss connection between temporal response and cutoff frequency

Go back to 10 u

Now instead of a DC input hear let's go with a square wave with 20 Hz

This is going to cycle between 5 V to –5 V 20 times a second, so one cycle every 50 ms.

Notice the voltage across the capacitor takes a little bit of time to follow this, but it catches up and is the same as the square wave most of the time

That means this signal at a frequency of 20 Hz would 'pass'.

Now let's crank this up to 85 Hz, which happens to be the cutoff frequency of this filter.

Notice that as soon as the capacitor 'catches up' to the source voltage, it gets switched. So at this frequency, the source signal might pass, but it will be attenuated since the voltage across the capacitor is spending most of the time 'catching up' to the changing source

Now let's crank this up to 500 Hz, which is beyond the cutoff frequency.

Now you can see the capacitor voltage never has enough time to 'catch up' with the alternating source voltage. So some of the signal would pass but it would be significantly attenuated

If we crank this up even further to 5 kHz you can see there is basically no response from our output voltage. The 5 kHz input square wave is (almost) completely cutoff.

Now let's visualize what we've shown on a frequency response graph.

So here the x axis represents frequencies in a log scale, and the y axis represents how much of the source signal gets through to the ouput.

So if we go on this graph to the frequency we first showed of 20 Hz, you can see the the loss is small, and this is where our output signal was pretty close to the input signal

Then we go up to 80 hZ and you can see this curve has gone down a bit, this repsresents the –3dB where our output has lost about half the power of the input signal.

Then we go to 500 Hz and you can see it's further down,

And 5 kHz is of course further down still representing more attenuation of our source square wave

So you can see how this setup yields a low-pass filter, because it will pass the lower-frequency 20 Hz signal pretty closely, but will almost completely reject the 5 kHz squarewave.

So this is how a low pass filter works to allow lower frequencies and reject higher frequencies, and as discussed this is due to the time delay capacitors have with storing electrical energy.

If you were able to follow this, then you should have a good fundamental understanding of how capacitors and low pass RC filters work, and if you understand this, then it should be relatively straight forward to extend this understanding to how high-pass filters work, and to how filters using inductors instead of capacitors.

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